Question

(2x-4)² = 0
equação de 2 grau!
alguém?
r:2)​

Answer 1

Resposta:

Existem duas formas para resolver:

1a forma

(2x-4)² = 0

(2x-4)=±√0

2x-4=0

2x=4

x=4/2

x=2

2a forma (mais trabalhosa)

(2x-4)² = 0

4x²-16x+16=0 (÷4)

x²-4x+4=0

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}-4x+4=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=-4~e~c=4\\\\\Delta=(b)^{2}-4(a)(c)=(-4)^{2}-4(1)(4)=16-(16)=0\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-4)-\sqrt{0}}{2(1)}=\frac{4-0}{2}=\frac{4}{2}=2\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-4)+\sqrt{0}}{2(1)}=\frac{4+0}{2}=\frac{4}{2}=2\\\\S=\{2,~2\}$