Question

2x+3y +z=1
3x+3y +z =8
2y +z+0=0

Answer 1

2x+3y+z=1
3x+3y+z=8
2y+z=0
z=-2y

2x+3y-2y=1
2x+y=1
y=1-2x
3x+3(1-2x)-2(1-2x)=8
3x+3-6x-2+4x=8
x+1=8
x=7
y=1-2.7
y=-13
z=-2.-13
z=26