Question

2x + 3x² -4x -2x = 2x² - 4

Answer 1

2x + 3$x^{2}$ - 4x -2x = 2$x^{2}$ - 4
⇒ 3x² - 2x² + 2x - 6x + 4 = 0
⇒ x² - 4x + 4 = 0
a = 1 ; b = - 4 ;  c = 4
Δ = (b)² - 4 . a . c
Δ = (- 4)² - 4 . 1 . 4
Δ = 16 - 16
Δ = 0
x =$\frac{ - b +/- √Δ }{2 . a}$
x = $\frac{4 +/- √0}{2 . 1}$
x' = $\frac{4 + 0}{2}$
x' = 2
x" = $\frac{4 - 0}{2}$
x" = 2