Question

(2x-3) (x-8) =34 Me Ajudem

Answer 1

(2x-3).(x-8)=34

2x²-16x-3x+24=34

2x²-19x=10

2x²-19x-10=0

Isso vc pode resolver pela formula de Baskara:

Δ=b²-4.a.c sendo que:

A=2

B= -19

c= -10

Δ=- ( -19)²-4.2. -10

Δ=361+80

Δ=441

X= -b +-√Δ/2.a

X= -(-19)+-21/2.2

x=+19+-21/4.

x¹= +19-21/4

x¹= -2/4

x¹= -0,5

x²= 19+21/4

x²=40/4

x²= 10.

Logo vc vai usar o 10.

(2.10-3).(10-8)=34

(20-3).(2)=34

17.2=34