(2x-3).(x+4)=(x+2).(5×-6)
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(2x-3)(x+4) = 2x²+8x-3x-12 = 2x²+5x-12
(x+2)(5x-6) = 5x²-6x+10x-12 = 5x²+4x-12
2x²+5x-12 = 5x²+4x-12
2x²+5x-12-5x²-4x+12=0
-3x²+x=0
x(-3x+1)=0
x' = 0
-3x+1=0
-3x=-1 x(-1)
x=1/3
S:{0;1/3}
(x+2)(5x-6) = 5x²-6x+10x-12 = 5x²+4x-12
2x²+5x-12 = 5x²+4x-12
2x²+5x-12-5x²-4x+12=0
-3x²+x=0
x(-3x+1)=0
x' = 0
-3x+1=0
-3x=-1 x(-1)
x=1/3
S:{0;1/3}
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