Question

(2x+½)² me ajudem por favor

Answer 1

Ajudo Sim : 

$(2x+\frac{1}{2})^2=(\frac{4x+1}{2})^2=(\frac{1}{2})^2(4x+1)^2=\frac{1}{4}([4x]^2+2[4x][1]+[1]^2)\\=\boxed{\frac{1}{4}(16x^2+8x+1)}$

Answer 2

produto notavel

(a + b)² = a² + 2ab + b²

(2x + ½)² = (2x)² + 2.2x.½ + (½)²

= 4x² + 2x + ¼

se for pra resolver...

entao..

∆ = b² - 4ac
∆ = 2² - 4.4.¼
∆ = 4 - 4
∆ = 0

x = -b ± √∆ /2a
x = -2/2.4

x' = x" = -2/8 ÷ 2
x' = x" = -1/4

Espero ter ajudado