Question

2x^2 - 8x + 8 =0 ?
Fórmula de bhaskara

Answer 1

2x^2-8x+8=0
delta=b^2-4ac
delta=(-8)^2-4.2.8
delta=64-64
delta=0
x=-b-/+ raiz de delta/2a
x=-(-8)-0/2.2
x=8-0/4
x=8/4
x=2