Question

-2x^2+8x-8=0 ????????????

Answer 1

-2x²+8x-8=0 (÷-2) x²-4x+4=0 ∆=b²-4ac ∆=(-4)²-4(1)(4) ∆= 16-16 ∆=0 X'=X" --> X'= -b/2a --> X'= -(-4)/2(1) -->X'= 2

Answer 2

espero que dê pra entender