Question

∆=2x^2-7x+6=0 equação

Answer 1

Oi xuxu,

$2 x^{2} -7x+6=0$
Δ $=b^{2}-4.a.c$
Δ$= 49-4.2.6$
Δ$=49-48$
Δ$=1$

$\frac{-b+ \sqrt{delta}}{2.a} = \frac{7+1}{2.2} = \frac{8}{4} = 2 \\ \\ \frac{-b- \sqrt{delta} }{2.a} = \frac{7-1}{2.2} = \frac{6}{4} = \frac{3}{2} = 1,5 \\ \\ x_{1}= 2 \\ x_{2}=1,5$
$S= (2;1,5)$

Bons estudos.