Question

2x^2=7x+3

Plz?helpame

Answer 1

2x² = 7x + 3

2x² - 7x - 3 = 0

∆ = (-7)² - 4.2.(-3)

∆ = 49 + 24

∆ = 73

$x = \frac{ - ( - 7) + - \sqrt{73} }{2 \times 2}$

$x = \frac{7 + - \sqrt{73} }{4}$

$x' = \frac{7 - \sqrt{73} }{4} \\ x" = \frac{7 + \sqrt{73} }{4}$

Answer 2

2x^2 - 7x - 3 = 0
a = 2, b = - 7 e c = - 3

delta = b^2 - 4 * a * c
delta = (- 7)^2 - 4 * 2 * (- 3)
delta = 49 + 24
delta = 73

x = [-b +- delta^(1/2)]/2*a
x = [7 +- 73^(1/2)]/2*2
x = [7 +- 73^(1/2)]/4

x’ = [7 + 73^(1/2)]/4
x” = [7 - 73^(1/2)]/4

Solução = {[7 - 73^(1/2)]/4, [7 - 73^(1/2)]/4}