Question

2x^2-3x=2x-1 alguem sabe?

Answer 1

$2x^{2}-3x=2x-1 \\ 2x^{2}-5x+1=0 \\ delta=25-8=17 \\ \\ x'= \frac{5+ \sqrt{17} }{2.2} = \frac{5+ \sqrt{17} }{4} \\ \\ x''= \frac{5- \sqrt{17}}{2.2} = \frac{5- \sqrt{17}}{4} \\ \\ S=[ \frac{5- \sqrt{17}}{4}; \frac{5+ \sqrt{17}}{4} ]$