Question

(2x-1) × (3x² + 4x)​

Answer 1

Resposta:

${6x}^{2} + 8x - {3x}^{2} - 4x$

${3x}^{2} + 4x = 0$

$delta = {4}^{2} - 4 \times 3 \times 0$

$y1 = \frac{ - 4 + \sqrt{16} }{2 \times 3} = 0$

$y2 = \frac{ - 4 - \sqrt{16} }{2 \times 6} = \frac{ - 8}{6} = \frac{ - 4}{3}$