Question

(2x - 1/2 - 1/6y ) - ( 1/2xy - 1/9y + 1/4x) como fazer essa conta precisa de calculo para eu entender

Answer 1

(2x - 1/2 - 1/6 y) - (1/2 xy - 1/9 y + 1/4 x)

2x - 1/2 - 1/6 y - 1/2 xy + 1/9 y - 1/4 x

2x/1 - x/4 - 1/2 - 1/6 y + 1/9 y - 1/2 xy

(4 . 2x)/(4 . 1) - x/4 - 1/2 - y/6 + 1/9 y - 1/2 xy

8x/4 - x/4 - 1/2 - 3y/(3 . 6) + 2y/(2 . 9) - 1/2 xy

(8x - x)/4 - 1/2 - 3y/18 + 2y/18 - 1/2 xy

7x/4 - 1/2 - 3y/18 + 2y/18 - 1/2 xy

7/4 x - 1/2 (- 3y + 2y)/18 - 1/2 xy

7/4 x - 1/2 - y/18 - 1/2 xy

atte. yrz

Answer 2

Resposta:

$\sf{segue \: abaixo \: a \: resposta}$

Explicação passo-a-passo:

$\sf{(2x - 1/2 - 1/6y ) - ( 1/2xy - 1/9y + 1/4x)}$

$\sf{2x - \frac{1}{2} - \frac{1}{6} y - ( \frac{1}{2} xy - \frac{1}{9}y + \frac{1}{4}x) }$

$\sf{2x - \frac{1}{2} - \frac{1}{6} y - \frac{1}{2}xy + \frac{1}{9} y - \frac{1}{4}x }$

$\sf{ \frac{7}{4}x - \frac{1}{2} - \frac{1}{6} y - \frac{1}{2} xy + \frac{1}{9} y }$

$\boxed{\boxed{{\sf{ \frac{7}{4}x - \frac{1}{2} - \frac{1}{18} y - \frac{1}{2} xy}}}}$