Question

2ab- [3b-(2a +3b-ab)]

 

(a/2 +2x +1) - (x - 3a/4 - 2/5)

Answer 1

Olá, ragi.

 

 

 

$<var>2ab- [3b-(2a +3b-ab)]=2ab-[3b-2a-3b+ab]=</var>$

 

$<var>=2ab+2a-ab=a(2b+2-b)=a(b+2)</var>$

 

 

 

$<var>(\frac{a}2 +2x +1) - (x - \frac{3a}4 - \frac25)=\frac{a}2 +2x +1-x+\frac{3a}4 +\frac25=</var>$

 

$<var>=\frac{2a+3a}4+x+\frac{5+2}5=\frac54 a + x + \frac75</var>$

Answer 2

 Regi,

 

2ab- [3b-(2a +3b-ab)]

 

2ab - [3b -2a - 3b + ab]

 

2ab - [- 2a + ab]

 

2ab + 2a - ab

 

ab + 2a

 

a(b + 2)  RESULTADO FINAL

 

(a/2 +2x +1) - (x - 3a/4 - 2/5)

 

a/2 + 2x + 1 - x + 3a/4 + 2/5

 

a(1/2 + 3/4) + x + (1 + 2/5)

 

a(2/4 + 3/4) + x + (5/5 + 2/5)

 

a(5/4) + x + (7/5)

 

5/4a + x + 7/5  RESULTADO FINAL