Question

[2⁹:(2².2)³]-³ plmrdds me ajudem ​

Answer 1

Resposta:

[2⁹:(2².2)³]-³ = 1

Explicação:

Aplicar as propriedades dos expoentes: $a^{-b} = \frac{1}{a^{b} }$

$(\frac{2^{9} }{(2^{2} * 2)^{3} } )^{-3} = \frac{1}{(\frac{2^{9} }{(2^{2} * 2)^{3} } )^{3} } \\\\= \frac{1}{(\frac{2^{9} }{(2^{2} * 2)^{3} } )^{3} } \\\\=( \frac{2^{9} }{(2^{2} * 2)^{3} } )^{3} = 1$

$= \frac{1}{1}$

Aplicar a regra $\frac{a}{1} = a$

= 1