Question

27 pontos pra quem me ajudar com a resolução.

Answer 1

$f(x)=\sqrt{3}\cdot(x^2)+1$

$f(\sqrt{3})=\sqrt{3}\cdot(\sqrt{3})^2+1=(\sqrt{3})^3+1=3\sqrt{3}+1$.

$f(\sqrt{2})=\sqrt{3}\cdot(\sqrt{2})^2+1=2\sqrt{3}+1$

Assim, $f(\sqrt{3})-f(\sqrt{2}+1=3\sqrt{3}+1-2\sqrt{3}-1+1=\sqrt{3}+1$ e 

$(\sqrt{3}-1)[f(\sqrt{3}-f(\sqrt{2})+1]=(\sqrt{3}-1)(\sqrt{3}+1)=(\sqrt{3})^2-1^2=3-1=2$

Letra A

Answer 2

$f(x)= \sqrt{3}x^2+1\\ \\ ( \sqrt{3}-1)[f(\sqrt3)-f(\sqrt2)+1]=\\ \\ ( \sqrt{3}-1)\{ \sqrt{3}*(\sqrt3)^2 +1- [\sqrt3*(\sqrt2)^2+1]+1\}=\\ \\ (\sqrt3-1)\{3\sqrt3+1-2\sqrt3-1+1\}=\\ \\ (\sqrt3-1)(\sqrt3+1)=3-1=2$