Matemática, perguntado por italo6289, 10 meses atrás

27. Calcule.
a) mmc (50, 75)
b) mmc (60, 24)
c) mmc (28, 48)
d) mmc (10, 12, 45)
e) mmc (6, 8, 12, 15)
f) mmc (12, 18, 36, 40)​

Soluções para a tarefa

Respondido por miiiki
0
A)
50 | 2
25 | 5
5 | 5
1
Logo 50= 2*5^2

75 | 3
25 | 5
5 | 5
1
Logo 75= 3*5^2
MMC (50, 75) = 2*3*5^2 = 150

B)
60 | 2
30 | 2
15 | 3
5 | 5
1
Logo 60= 2^2*3*5

24 | 2
12 | 2
6 | 2
3 | 3
1
Logo 24 = 2^3*3
MMC (60,24) = 2^3*3*5 = 120

C)
28 | 2
14 | 2
7 | 7
1
Logo 28= 2^2*7

48 |2
24 | 2
12 | 2
6 | 2
3 | 3
1
Logo 48 = 2^4*3
MMC (28,48) = 2^4*7*3 = 336

D)
10 | 2
5 | 5
1
Logo 10 = 2*5

12 | 2
6 | 2
3 | 3
1
Logo 12= 2^2*3

45 | 3
15 | 3
5 | 5
1
Logo 45= 3^2*5
MMC (10,12,45) = 2^2*3^2*5 = 180

E)
6 | 2
3 | 3
1
Logo 6 = 2*3

8|2
4 |2
2|2
1
Logo 8= 2^3

12 | 2
6 | 2
3 | 3
1
Logo 12 = 2^2*3

15 | 3
5 | 5
1
Logo 15= 3*5
MMC (6, 8, 12, 15) = 2^3*3*5 = 120

F)
12 | 2
6 | 2
3 | 3
1
Logo 12 = 2^2*3

18 | 2
9 | 3
3 | 3
1
Logo 18 = 2*3^2

36 | 2
18 | 2
9 | 3
3 | 3
1
Logo 36 = 2^2*3^2

40 | 2
20 | 2
10 | 2
5 | 5
1
Logo 40 = 2^3*5
MMC (12, 18, 36, 40) = 2^3*3^2*5 = 360
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