Question

27⅓+4½

preciso urgente​

Answer 1

Resposta:

5

Explicação passo a passo:

$x^{\frac{a}{b} }=\sqrt[b]{x^a}$

então

$27^{\frac{1}{3} }=\sqrt[3]{27^1}=3$

$4^{\frac{1}{2}}=\sqrt{4} =2$

2 + 3 = 5

Answer 2

$(27)^{\frac{1}{3} } + (4)^{-\frac{1}{2} }$

$\sqrt[3]{27} + (\frac{1}{4})^{\frac{1}{2} }$

$3+\sqrt{\frac{1}{4} }$

$3+\frac{1}{2}$

$\frac{6+1}{2} = \frac{7}{2}$