Question

26) Dada à função do 1º grau F(x) = 4x + 10. Determinar:
a. F(0) b . F(-1) c . F( 1/3)

Answer 1

$f(x) = 4x + 10$

A) F(0)
$f(0) = 4 \times 0 + 10 \\ \\ f(0) = 4 + 10 \\ \\ f(0) = 14$

B)F(–1)
$f( - 1) = 4 \times - 1 + 10 \\ \\ f( - 1) = - 4 + 10 \\ \\ f( - 1) = 6$

C) F(1/3)
$f( \frac{1}{3} ) = 4 \times \frac{1}{3} + 10 \\ \\ \frac{4 \times 1}{1 \times 3} + 10 \\ \\ \frac{4}{3} + 10 \\ \\ fazer \: mmc \: \\ \\ \frac{4 + 30}{3} \\ \\ f( \frac{1}{3} ) = \frac{34}{3}$

Answer 2

a) 4×0+10= 10. F(0) = 10

b) 4×(-1)+10
-4+10 = 6. F(-1) = 6

c) 4×1/3+10
4/1×1/3 = 4/3
4/3+ 10/1 = 4/3 + 30/3
= 34/3