Question

23. Sabendo que AB = 4 u.c. e BC = 3 u.c., calcule OD.
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Answer 1

Explicação passo-a-passo:

Pelo Teorema de Pitágoras:

$\sf \overline{AC}^2=3^2+4^2$

$\sf \overline{AC}^2=9+16$

$\sf \overline{AC}^2=25$

$\sf \overline{AC}=\sqrt{25}$

$\sf \overline{AC}=5~u.c.$

Temos que:

$\sf b^2=a\cdot m$

$\sf \overline{AB}^2=\overline{AC}\cdot\overline{OD}$

$\sf 4^2=5\cdot\overline{OD}$

$\sf 16=5\cdot\overline{OD}$

$\sf \overline{OD}=\dfrac{16}{5}$

$\sf \red{\overline{OD}=3,2~u.c.}$