Question

2³+2³+2³+2³
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(2³)²+(2³)²

Answer 1

$\frac{ {2}^{3} + {2}^{3} + {2}^{3} } {( {2} {}^{3} )^{2} + {(2 {}^{3} ) {}^{} }^{2} }$

${2}^{3} = 8$

${(2 {}^{3} )}^{2} = { {2}^{6} }^{} \\ {2}^{6} = 64$

substituindo :

$= \frac{8 + 8 + 8}{64 + 64}$

adicionando :

$= \frac{24}{128}$