Question

22-resolva a equaçao exponencial:(3elevado(2x-3))elevado(x+4)=1 (calculo na resposta ) URGENTE

Answer 1

$(3^{2x-3})^{x+4}=1 \\ \\ (3^{(2x-3)*(x+4)})=1 \\ \\ (3^{2x^2+8x-3x-12})=1 \\ \\ (3^{2x^2+5x-12})=1 \\ \\ Log_3(3^{2x^2+5x-12})=Log_31 \\ \\ (2x^2+5x-12)* Log_33= log_31 \\ \\ (2x^2+5x-12)* (1)=0 \\ \\ 2x^2+5x-12= 0$

$(x+4)(2x-3)= 0 \\ \\ x+4=0\qquad \qquad 2x-3=0 \\ \\ \boxed{x_1= -4} \qquad \qquad \boxed{x_2= \frac{3}{2} }$