Question

[2²:2³] ·(2²-2²³) ²=

Answer 1

Resposta:

$\left[\frac{2^2}{2^3}\right]\cdot \left(2^2-2^{23}\right)^2=\frac{1}{2}\cdot \:8388604^2$

$\left(\frac{2^2}{2^3}\right)\left(2^2-2^{23}\right)^2\\\\\frac{2^2}{2^3}\left(2^2-2^{23}\right)^2\\\\\frac{1}{2}\left(2^2-2^{23}\right)^2\\\\\frac{1}{2}\left(4-2^{23}\right)^2\\\\\frac{1}{2}\cdot \:8388604^2$

Explicação:

Answer 2

Explicação:

$( {2}^{2} \div {2}^{3} ) \times ( {2}^{2} - {2}^{23} {)}^{2}$

${2}^{ - 1} \times (4 - {2}^{23} {)}^{2}$

$\frac{1}{2} \times (16 - 4 \times {2}^{24} + {2}^{46} )$

$\frac{1}{2} \times (16 - {2}^{2} \times {2}^{24} + {2}^{46} )$

$\frac{1}{2} \times (16 - {2}^{26} + {2}^{46} )$

Solução

$8 - {2}^{25} + {2}^{45}$