Question

20x^2 - 9x +1 =0
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Answer 1

a = 20          

b = - 9

c = 1

Δ = b^2 - 4ac

Δ = (-9)^2 - 4 * 20 * 1

Δ = 81 - 80

Δ = 1

x = - b ± √Δ / 2a

x = -(-9) ± √1 / 2 * 20

x = 9 ± 1 / 40

x1 = 9 + 1 / 40 = 10/40 = 1/4

x2 = 9 - 1 / 40 = 8/40 = 1/5