Question

[2°(10-4²:2)+6²]:(2³-2²)

Answer 1

$\dfrac{[ \ 2^0 (10- 4^2 \div 2) + 6^2 ]}{(2^3 - 2^2) } \\ \\ \\ \dfrac{[ \ 1. (10- 16 \div 2) + 36 ]}{(8 - 4) } \\ \\ \\ \dfrac{[ \ 1. (10 - 8) + 36 ]}{4 } \\ \\ \\ \dfrac{[ \ 1. 2 + 36 ]}{4 } \\ \\ \\ \dfrac{[ 2 + 36 ]}{4 } \\ \\ \\=\ \textgreater \ \dfrac{38}{4}$

Answer 2

[2º(10-4²:2)+6²] : (2³-2²)
[2º(10-16:2)+6²] : (8-4)
[2º(10-8)+6²] :4
[2º(2)+6²]:4
[1(2)+36] :4
[2+36]:4
38:4=9,5