Question

2) x² + x – 7 = 5
calculo completo com delta PASSO A PASSO POR FAVOR

Answer 1

Resposta:

$x^2+x-7=5=x=3,\:x=-4$

$x^2+x-7=5\\\\x^2+x-7-5=5-5\\\\x^2+x-12=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \left(-12\right)}}{2\cdot \:1}\\\\x_{1,\:2}=\frac{-1\pm \:7}{2\cdot \:1}\\\\x_1=\frac{-1+7}{2\cdot \:1},\:x_2=\frac{-1-7}{2\cdot \:1}\\\\x=3,\:x=-4$

Answer 2

Explicação passo a passo:

x² + x – 7 = 5

x² + x – 7 - 5 = 0

x² + x - 12 = 0

a = 1

b = 1

c = -12

Δ = b² - 4ac

Δ = 1² - 4.1.(-12)

Δ = 1 + 48

Δ = 49

x = -b±√Δ/2a

x = -1±√49/2.1

x = -1±7/2

x' = -1+7/2 = 6/2 = 3

x'' = -1-7/2 = -8/2 = -4

Espero ter ajudado! ;-)

Bons estudos! ^-^