Question

2(x²+3X)-X+1=-x² ache o coeficiente de abc!!

Answer 1

2×(x^2+3×x)-x+1=-x^2

2×(x^2+3×x)-x+1=-x^2
distribuir 2 através de parênteses

2×x^2+2×3×x-x+1=-x^2

2×x^2+6×x-x+1=-x^2

2×x^2+5×x+1=-x^2
subtrair -x^2

2×x^2+5×x+1--x^2=0

3×x^2+5×x+1=0
Resolver pela fórmula x_1,2=(-b)±(sqrt(b^2-4×a×c))/2×a

a=3, b=5, c=1
x_1,2=(-5)±(sqrt(5^2-4×3))/2×3

x_1,2=(-5)±(sqrt(5^2-12))/2×3

x_1,2=(-5)±(sqrt(5^2-12))/(2×3)

x_1,2=(-5)±(sqrt(25-12))/(2×3)

x_1,2=(-5)±(sqrt(13))/(2×3)

x_1,2=(-5)±(3.606)/(2×3)

 solucao
x_1=(-5)+(3.606)/(2×3)

x_1=(-5+3.606)/(2×3)

x_1=(-5+3.606)/6

x_1=-1.394/6

x_1=-0.232
resolvido para x_1