Question

2(x elevado a 2 + 3)=7x

Answer 1

Olá!!!

Resolução!!!

2 ( x² + 3 ) = 7x
2x² + 6 = 7x
2x² - 7x = - 6
2x² - 7x + 6 = 0

a = 2, b = - 7, c = 6

∆ = b² - 4ac
∆ = ( - 7 ) - 4 • 2 • 6
∆ = 49 - 48
∆ = 1

x = - b ± √∆ / 2a
x = - ( - 7 ) ± √1 / 2 • 2
x = 7 ± 1 / 4
x' = 7 + 1 / 4 = 8/4 = 2
x" = 7 - 1 / 4 = 6/4 : 2 = 3/2

S = { 2, 3/2 }

Espero ter ajudado!!!

Answer 2

Olá Alicia, tudo bem?

Utilize a propriedade distributiva para resolver.

Vamos lá
$2(x^{2}+3)=7x\\ (2 \times x^{2})+(2 \times 3)=7x\\ 2x^{2}+6=7x\\ 2x^{2}-7x+6=0\\\\ Utilize\:a\: f\'ormula\:de\:Bhaskara\:para\:resolver:\\\\ x=\frac{-b\pm \sqrt{b^{2}-4\times a \times c} } {2\times a}\\\\ x=\frac{-(-7)\pm \sqrt{(-7)^{2}-4\times 2 \times 6} }{2\times 2}\\\\ x=\frac{7\pm \sqrt{49-48} }{4}\\\\ x=\frac{7\pm \sqrt{1} }{4}\\\\ x=\frac{7 \pm 1}{4}\\\\ x'= \frac{7+1}{4}=\frac{8}{4} = \boxed{2} \\\\ x''= \frac{7-1}{4}=\frac{7-1}{4} = \frac{6^{\div 2}}{4^{\div 2}} = \boxed{ \frac{3}{2} }$

$S= \{ \frac{3}{2} , 2\: \}$




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Espero ter ajudado
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