Question

(2/x-3)-(4x/x²-9)=(7/x+3)

Answer 1

2/x-3-(4x/x^2-9)=7/x+3
2/x-3-4x/x^2+9=7/x+3
2/x+6-4x/x^2=7/x+3
$\frac{2}{x}$+6-4x/x^2=7/x+3
$\frac{2}{x}$+6-$\frac{4x}{x^2}$=7x+3
$\frac{2}{x}$+6-$\frac{4}{x^2^-^1}$=7x+3
$\frac{2}{x}$+6-$\frac{4}{x^1}$=7/x+3
$\frac{2}{x}$+6-$\frac{4}{x}$=7/x+3
$\frac{2-4}{x}$+6=7/x+3
$\frac{-2}{x}$+6=7/x+3
-$\frac{2}{x}$+6=7/x+3
-$\frac{2}{x}$+6=$\frac{7}{x}$+3
-$\frac{2}{x}- \frac{7}{x}$=3-6
$\frac{-2-7}{x}$=3-6
$\frac{-9}{x}$=3-6
$\frac{-9}{x}$=-3
-$\frac{9}{x}$=-3
$\frac{9}{x}$=3
$\frac{9}{3}$=x
3=x
x=3