Question

2.(x+3)4.(x-1 alguem ajuda pfv

Answer 1

Explicação passo-a-passo:

$2(x + 3)4(x - 1) = 0 \\ < = > 8(x + 3)(x - 1) = 0 \\ < = > 8( {x}^{2} + 2x - 3) = 0 \\ < = > 8 {x}^{2} + 16x - 24 = 0 \\ < = > 8 {x}^{2} + 8x + 8x - 24 = 0 \div 8 \\ < = > {x}^{2} + 2x - 3 = 0 \\ \\ delt = {b}^{2} - 4ac = {2}^{2} - 4 \times 1 \times ( - 3) = 16 \\ x = \frac{2 - \sqrt{16} }{2} = \frac{2 - 4}{2} = \frac{ - 2}{2} = - 1 \\ x = \frac{ - 2 + \sqrt{16} }{2} = \frac{ - 2 + 4}{2} = \frac{2}{2} = 1$