Question

2.(x-2)+5.(2-x)+6.(x+10)=0 me ajd pvr

Answer 1

2 ( x - 2 ) + 5 ( 2 - x ) + 6 ( x + 1 ) = 0
2x - 4 + 10 - 5x + 6x + 6 = 0
2x - 5x + 6x = 0 - 6 - 10 + 4
3x = - 12
x = - 12 / 3
x = - 4
Espero ter ajudado

Answer 2

 Boa Tarde !!!!

2(x-2)+5(2-x)+6(x+10)=0

2x-4+10-5x+6+60=0

2x-5x=4-10-6-60

-3x=-6-66

x=$\frac{-72}{-3}$

x=24