Matemática, perguntado por kauaarjdeandrade, 4 meses atrás

2⋅(x−12)=−5x: quanto é X?

Soluções para a tarefa

Respondido por Usuário anônimo
2

Resposta:

2x(x-12) = -5\\2x^2 -24x = -5\\2x^2 - 24x -(-5) = 0\\\\x = \frac{-b±\sqrt{b^2} -4ac }{2a} \\\\2x^2 - 24x + 5 = 0\\a= 2\\b = -24\\c= 5\\\\x = \frac{-(-24)±\sqrt{(-24)^2 } - 4 . 2 . 5 }{2.2} \\\\x=\frac{24±\sqrt{576 - 4 . 2 . 5} }{2 . 2} \\\\x = \frac{24±\sqrt{576 -40} }{2.2} \\\\x = \frac{24±\sqrt{536} }{2.2} \\\\x = \frac{24±\sqrt{2 . 268} }{2.2} \\\\x = \frac{24±\sqrt{2.2.134} }{2.2} \\\\x = \frac{24±\sqrt{2.2.2.67} }{2.2} \\x = \frac{24±\sqrt{2.\sqrt{2.\sqrt{2.67} } } }{2.2} \\

Continuação!

x =\frac{24±2\sqrt{2.67} }{2.2}   \\\\x = \frac{24±2\sqrt{134} }{2.2} \\\\x= \frac{24±2\sqrt{134} }{4} \\\\x= \frac{24+2\sqrt{134} }{4}\\\\x = \frac{24-2\sqrt{134} }{4} \\\\x = \frac{12+\sqrt{134} }{2} \\\\x= \frac{12-\sqrt{134} }{2} \\\\X = \frac{12±\sqrt{134} }{2}

Perguntas interessantes