Question

2) Vamos resolver as inequações:

a) 3x² + 10x + 7 < 0
b) x² – 6x + 9 > 0
c) x² – 4x ≥ 0
d) 9 – x² > 0
alguem me ajuda,é pra hoje

Answer 1

A)

$\left(x+1\right)\left(3x+7\right)<0$

$-\frac{7}{3}<x<-1$

B)

$\left(x-3\right)^2>0$

$x-3<0\quad \mathrm{ou}\quad \:x-3>0$

$x<3\quad \mathrm{ou}\quad \:x>3$

C)

$x^2-4x\ge \:0$

$x\left(x-4\right)\ge \:0$

$x\le \:0\quad \mathrm{ou}\quad \:x\ge \:4$

D)

$9-x^2>0$

$-x^2>-9$

$\left(-x^2\right)\left(-1\right)<\left(-9\right)\left(-1\right)$

$x^2<9$

$-3<x<3$

Espero ter ajudado