2. Utilizando as matrizes do exercício anterior, determine a matriz (X), tal que, A B X t . (A) 4 6 3 5 (B) 4 6 3 0 (C) 4 0 3 5 (D) 4 6 3 5 (E) N.d.a
Soluções para a tarefa
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A matriz X é determinada por
.
As alternativas são:
a)![\left[\begin{array}{ccc}-3&5\\-4&6\end{array}\right] \left[\begin{array}{ccc}-3&5\\-4&6\end{array}\right]](https://tex.z-dn.net/?f=++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%26amp%3B5%5C%5C-4%26amp%3B6%5Cend%7Barray%7D%5Cright%5D+)
b)![\left[\begin{array}{ccc}3&0\\4&6\end{array}\right] \left[\begin{array}{ccc}3&0\\4&6\end{array}\right]](https://tex.z-dn.net/?f=+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26amp%3B0%5C%5C4%26amp%3B6%5Cend%7Barray%7D%5Cright%5D+)
c)![\left[\begin{array}{ccc}3&5\\4&0\end{array}\right] \left[\begin{array}{ccc}3&5\\4&0\end{array}\right]](https://tex.z-dn.net/?f=+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26amp%3B5%5C%5C4%26amp%3B0%5Cend%7Barray%7D%5Cright%5D+)
d)![\left[\begin{array}{ccc}3&5\\4&6\end{array}\right] \left[\begin{array}{ccc}3&5\\4&6\end{array}\right]](https://tex.z-dn.net/?f=+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26amp%3B5%5C%5C4%26amp%3B6%5Cend%7Barray%7D%5Cright%5D+)
e) N.d.a
As matrizes A=(aij) e B=(bij), sendo aij = 3i + 2j e bij = i + j, foram definidas por:
![A= \left[\begin{array}{ccc}5&7\\8&10\end{array}\right] A= \left[\begin{array}{ccc}5&7\\8&10\end{array}\right]](https://tex.z-dn.net/?f=A%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26amp%3B7%5C%5C8%26amp%3B10%5Cend%7Barray%7D%5Cright%5D+)
![B=\left[\begin{array}{ccc}2&3\\3&4\end{array}\right] B=\left[\begin{array}{ccc}2&3\\3&4\end{array}\right]](https://tex.z-dn.net/?f=+B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26amp%3B3%5C%5C3%26amp%3B4%5Cend%7Barray%7D%5Cright%5D+)
Para calcularmos a matriz X precisamos calcular a matriz transposta de A.
Para isso, o que era linha vira coluna e o que era coluna vira linha:
![A^T=\left[\begin{array}{ccc}5&8\\7&10\end{array}\right] A^T=\left[\begin{array}{ccc}5&8\\7&10\end{array}\right]](https://tex.z-dn.net/?f=+A%5ET%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26amp%3B8%5C%5C7%26amp%3B10%5Cend%7Barray%7D%5Cright%5D+)
Portanto, a matriz
é:
![X = \left[\begin{array}{ccc}5&8\\7&10\end{array}\right] -\left[\begin{array}{ccc}2&3\\3&4\end{array}\right] X = \left[\begin{array}{ccc}5&8\\7&10\end{array}\right] -\left[\begin{array}{ccc}2&3\\3&4\end{array}\right]](https://tex.z-dn.net/?f=X+%3D++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26amp%3B8%5C%5C7%26amp%3B10%5Cend%7Barray%7D%5Cright%5D+-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26amp%3B3%5C%5C3%26amp%3B4%5Cend%7Barray%7D%5Cright%5D)
![X= \left[\begin{array}{ccc}3&5\\4&6\end{array}\right] X= \left[\begin{array}{ccc}3&5\\4&6\end{array}\right]](https://tex.z-dn.net/?f=X%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26amp%3B5%5C%5C4%26amp%3B6%5Cend%7Barray%7D%5Cright%5D+)
Logo, a alternativa correta é a letra d).
As alternativas são:
a)
b)
c)
d)
e) N.d.a
As matrizes A=(aij) e B=(bij), sendo aij = 3i + 2j e bij = i + j, foram definidas por:
Para calcularmos a matriz X precisamos calcular a matriz transposta de A.
Para isso, o que era linha vira coluna e o que era coluna vira linha:
Portanto, a matriz
Logo, a alternativa correta é a letra d).
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