Question

2) Transformar

a) 90°c= _9f(c)113°f=°c
b) 10°c= _°f(d) 41°f=°c

Answer 1

Formula : TC/5=TF-32/9

a) 90/5=TF-32/9
5TF-160=180
5TF= 180+160
5TF= 340
TF= 340/5
TF= 68°F

B) 10/5=TF-32/9
5TF-160=90
5TF=90+160
5TF= 250
TF= 250/5
TF= 50°F

C) TC/5=113-32/9
9TC=565-160
9TC=405
TC= 405/9
TC= 45°C

D) TC/5=41-32/9
9TC=205-160
9TC= 45
TC= 45/9
TC= 5°C

Espero ter ajudado!