Question

2) Sendo log 2 = a, log 3 = b e log 5 = c. calcule a) log 6 b) log 3/5 c) log 15 d) log 30 e) log e2/3​

Answer 1

Resposta:

a) log6 = log(2.3)= log2+log3= a+b

b) log3/5= log3-log5

mas log 5 = log10/2= log10-log2= 1-a

assim, log3/5= b-(1-a)=b+a-1

c) log 15= log(3.5)= log3+log5= b+1-a

d)log30= log(3.10)= log3+log10= 1+b

e) log2/3= log2-log3= a-b