Question

2.RESOLVA OS ÂNGULOS COMPLEMENTARES

por favor me ajudem​

Answer 1

Resposta:

Olá bom dia!

Ângulos complementares somam 90°.

a)

x + 40 + 3x + x - 10 = 90

x + 3x + x + 40 - 10 = 90

5x + 30 = 90

5x = 90 - 30

5x = 60

x = 60 : 12

x = 5

Então os ângulos medem:

x + 40 = 5 + 40 = 45°

3x = 3(5) = 15°

x - 10 = 45 - 10 = 35°

b)

2x + 10 + x = 90

3x = 80

x = $\frac{80}{3}$

$2(\frac{80}{3} ) + 10\\\\= \frac{160}{3} +10\\\\= \frac{160-30}{3} \\\\= \frac{130}{3}$

Provando:

$2(\frac{80}{3})+10+\frac{80}{3} \\\\= \frac{160}{3} +10 + \frac{80}{3} \\\\= \frac{160+30+80}{3} \\\\=\frac{270}{3} \\\\=90^o$