Question

2) Resolva as seguintes equações

a) 4x – 1 = 3 ( x – 1)

b) 3( x – 2) = 2x – 4

c) 2( x – 1) = 3x + 4

d) 3(x – 1) – 7 = 15

e) 7 ( x – 4) = 2x – 3

f) 3 ( x –2) = 4(3 – x)

g) 3 ( 3x – 1) = 2 ( 3x + 2)

h) 7 ( x – 2 ) = 5 ( x + 3 )

i) 3 (2x – 1) = -2 ( x + 3)

j) 5x – 3( x +2) = 15

k) 2x + 3x + 9 = 8(6 –x)

l) 4(x+ 10) -2(x – 5) = 0

m) 3 (2x + 3 ) – 4 (x -1) = 3

n) 7 (x – 1) – 2 ( x- 5) = x – 5

o) 2 (3 – x ) = 3 ( x -4) + 15

p) 3 ( 5 – x ) – 3 ( 1 – 2x) = 42

q) ( 4x + 6) – 2x = (x – 6) + 10 +14

r) ( x – 3) – ( x + 2) + 2( x – 1) – 5 = 0

s) 3x -2 ( 4x – 3 ) = 2 – 3( x – 1)

t) 3( x- 1) – ( x – 3) + 5 ( x – 2) = 18

u) 5( x – 3 ) – 4 ( x + 2 ) = 2 + 3( 1 – 2x) ji​

Answer 1

Resposta:

não sei fazer ainda...me desculpe