Question

2^(n+4) + 2^(n+2) + 2^(n-1)/2^(n-2) + 2^(n-1)

Answer 1

Passo a passo

$\frac{2^{n+4}+2^{n+2}+2^{n-1}}{2^{n-2}+2^{n-1}} =\\ \\\frac{2^n*2^4+2^n+2^2+2^{n}+2^{-1}}{2^n*2^{-2}+2^n*2^{-1}}=$

$\frac{\not2^n(2^4+2^2+2^{-1})}{\not2^n(2^{-2}+2^{-1})}=$

$\boxed{ \frac{2^4+2^2+2^{-1}}{2^{-2}+2^{-1}}= \frac{164^{\div2}}{6\div2}=\boxed{\boxed{ \frac{82}{3} }} }$