Question

2^n+3 . 2² / 2^n-1






????????????​

Answer 1

$\frac{2^{n+3}\cdot2^2}{2^{n-1}}=\frac{2^{n+3+2}}{2^{n-1}} =\frac{2^{n+5}}{2^{n-1}} =2^{n+5-(n-1)}=2^{n+5-n+1}=2^{6}$

Answer 2

Resposta:

Explicação passo-a-passo:

O cara ai de cima sabe