Question

2.me ajudem pfvvvvv....
..... ..​

Answer 1

Resposta:

a) ΔT=12,5°C

b) C=800 cal/°C

Explicação:

400 cal   ---   1 min

 x   cal   ---   25 min

x=400.25

x=10000cal

Q=mcΔT

ΔT=10000/4000.0,2

ΔT=10000/800

ΔT=12,5°C

C=m.c

C=4000.0,2

C=800 cal/°C