Question

2 log x = log 4 + log 3x

Answer 1

.
$2log~x=log~4+log~3x \\ \\ log~x^2=log~4(3x)$

condição x >0

$x^2=12x \\ \\ x^2-12x=0 \\ \\ x(x-12)=0 \\ \\ x-12=0 \\ \\ x=12 \\ \\ x=0~~n/~~serve \\ \\ S=\{12\}$