Question

2 log x = log 2 + log (4x - 8)

Answer 1

Oi Pamela

2log(x) = log(2) + log(4x - 8)

log(x²) = log(2*(4x - 8)) = log(8x - 16)

x² = 8x - 16

x² - 8x + 16 = 0

delta
d² = 64 - 64 = 0

x = -b/2a = 8/2 = 4 

.