Question

2 grau por favor me ajudem

Answer 1

(2x - 4)² = 0
2x - 4 = +/- √0
2x - 4 = +/- 0
2x = 4 +/- 0
x = 4 +/- 0/2

x' = 4 + 0/2 = 4/2 = 2
x'' = 4 - 0 /2 = 4/2 = 2

S = {2}
Okais !!

Answer 2

(2x - 4)² = 0
(2x - 4)(2x - 4) = 0 
4x² - 8x - 8x + 16 = 0
4x² - 16x + 16 = 0 ÷ 4
x² - 4x + 4 = 0

a = 1 
b = - 4
c = 4

Δ = b² - 4ac
Δ = (-4)² - 4.1.4
Δ = 16 - 16
Δ = 0 

Agora aplica Bhaskara :

x = - b +/- √Δ /2a
x = - (-4) +/- √0 /2.1
x = 4 +/- 0/2

x' = 4 + 0/2 
x' = 4/2 
x' = 2

x'' = 4 - 0/2
x'' = 4/2
x'' = 2

S = {2}

Espero ter ajudado!!