Question

2. Fatore utilizando agrupamento:
ac + bc + ad + bd = c (a + b) + d (a + b) = (a + b) (c + d)
a) ax – ay + bx – by = a ( x – y ) + b ( x – y ) = ( a + b ) ( x – y )
b) 5ax – 5ay + bx – by =
c) x2 + 5x + ax + 5a =
d) 6a2 + 2ab – 3ac – bc =
e) t3 + t2 – 7t – 7 =
f) x3 – x2 – 9x + 9 =
g) 2b2 + 2 – b2k – k =
h) bx2 – 2by + 5x2 – 10y =
i) a2 + a + 2a + 2 =
j) cx + x + c + 1 =

Answer 1

Resposta:a) ac x bc + ad + bd

b) 3ax+ay + 3bx+by

c) 3ay-3a+by-b

d) 5am+ay+5bm +by

e) 8x-3xy+8-3y

PFV RESPONDA

1

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