Question

2) Encontre a f -1 (2) + f -1 (-2), sabendo que f(x) = 3x + 1.​

Answer 1

Resposta:

$f^{-1}(x)=3x+1\\ y = 3x+1\\x= 3y+1\\3y=x-1\\y=\frac{x-1}{3} \\\\f^{-1} (x)=\frac{x-1}{3} \\\\f^{-1} (2)=\frac{2-1}{3} =\frac{1}{3} \\\\f^{-1} (-2)=\frac{-2-1}{3} =\frac{-3}{3} = -1\\\\f^{-1} (2)+f^{-1} (-2)=\frac{1}{3}-1 = -\frac{2}{3}$

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