Question

(-2) elevado a -6 •8 elevado a 2 a 3 elevado a 0

Answer 1

$( - 2) {}^{ - 6} \times 8 {}^{2} + 3 {}^{0} = \\ \frac{1}{64} \times 64 + 1 = \\ \frac{1}{64} \times \frac{64}{1} + 1 = \\ 1 + 1 = 2$