Question

2 elevado a 4x+1 vezes 8 elevado -x+3=1/16

Answer 1

$2^{4x+1} .8 ^{-x+3} = \frac{1}{16}$

$2^{4x+1} .(2^3) ^{-x+3} =16 ^{-1}$

$2 ^{4x+1} .2 ^{-3x+9} =(2^4) ^{-1}$

$2 ^{4x+1} .2 ^{-3x+9} =2 ^{-4}$

$\not2 ^{4x+1-3x+9} =\not2 ^{-4}$

$4x+1-3x+9=-4$

$x+10=-4$

$x=-4-10$

$x=-14$