Question

2) Determine o vértice da função f(x) = -x² -x + 3 

(-9/2 , -6/7)

(-10 , 5)

(13/4 , -1/2)

(12/5 , 1,2)​

Answer 1

Resposta:

Explicação passo a passo:

  $f(x)=-x^{2} -x+3$

  $a=-1$

  $b=-1$

  $c=3$

  $\Delta=b^{2} -4ac$

  $\Delta=(-1)^{2} -4.(-1).(3)$

  $\Delta=1+12$

  $\Delta=13$

  $Vertice=>V(x_{v};y_{v})$

   

  $x_{v}=\frac{-b}{2a}$

  $x_{v}=\frac{-(-1)}{2.(-1)}$

  $x_{v}=\frac{1}{-2}$

  $x_{v}=-\frac{1}{2}$

  $y_{v}=\frac{-\Delta}{4a}$

  $y_{v}=\frac{-13}{4.(-1)}$

  $y_{v}=\frac{-13}{-4}$

  $y_{v}=\frac{13}{4}$

  $Portanto...$

 

   $Vertice=>V(x_{v};y_{v})=V(-\frac{1}{2} };\frac{13}{4} })$