Question

2) Determine o 4° termo no desenvolvimento (2x-1)^6

Answer 1

Resposta:

$t4 = \binom{6}{3} \times ({2x})^{3} \times ( - 1) {}^{3}$

$t4 = 20 \times 8x {}^{3} \times ( - 1)$

$t4 = - 160x {}^{3}$